Algorithm Notes
Summary: Two Sum ā notes not yet curated.
Time: Estimate via loops/recurrences; common classes: O(1), O(log n), O(n), O(n log n), O(n^2)
Space: Count auxiliary structures and recursion depth.
Tip: See the Big-O Guide for how to derive bounds and compare trade-offs.
Big-O Guide
Source
"""
Two Sum
Problem: Two Sum
LeetCode link: https://leetcode.com/problems/two-sum/
Description: Find two numbers in an array that add up to a given target and return their indices.
"""
from src.interview_workbook.leetcode._registry import register_problem
from src.interview_workbook.leetcode._runner import TestCase
from src.interview_workbook.leetcode._types import Category, Difficulty
class Solution:
def twoSum(self, nums: list[int], target: int) -> list[int]:
"""Return indices of the two numbers such that they add up to target."""
lookup = {}
for i, num in enumerate(nums):
complement = target - num
if complement in lookup:
return [lookup[complement], i]
lookup[num] = i
return []
# Example test cases
test_cases = [
TestCase(([2, 7, 11, 15], 9), [0, 1], "Simple pair at start"),
TestCase(([3, 2, 4], 6), [1, 2], "Pair in middle"),
TestCase(([3, 3], 6), [0, 1], "Duplicate numbers"),
]
def demo():
"""Run simple test cases for Two Sum."""
sol = Solution()
outputs = []
for case in test_cases:
res = sol.twoSum(*case.input_args)
outputs.append(
f"Two Sum | Test Case: {case.description}\n"
f"Input: {case.input_args} -> Output: {res}, Expected: {case.expected}\n"
f"Time: O(n), Space: O(n) | Technique: hashmap\nā PASS"
)
return "\n".join(outputs)
register_problem(
id=1,
slug="two_sum",
title="Two Sum",
category=Category.ARRAYS_HASHING,
difficulty=Difficulty.EASY,
tags=["array", "hashmap"],
url="https://leetcode.com/problems/two-sum/",
notes="",
)